Q: Find all solutions of the equation in the interval [0, 2pi )
tan²x – sec x = -1
(MULTIPLE CHOICE)
a. 0
b. pi/4 , 3pi/4 , 5pi/4 . 7pi/4
c. pi/6 , 5pi/6
d. 2pi/3 , pi , 4pi/3
A:
Let’s start with the equation:
tan²x – sec x = -1
Now, I see we have tan’s and sec’s mixed. We don’t like this… We want to have only one trig funciton (makes life easier)…. I do recall a trig identity we can use:
tan²x + 1 = sec²x
Manipulate this to get:
tan²x = sec²x – 1
Substitute this in to our original equation:
tan²x – sec x = -1
(sec²x – 1) – sec x = -1
sec²x – 1 – sec x = -1
Add 1 to both sides:
sec²x – sec x = 0
Factor:
sec x (sec x – 1) = 0
So, either sec x = 0 or sec x – 1 = 0
(1) sec x = 0 never… that never happens… so, we can through that out…
(2) sec x – 1 = 0
sec x = 1
1 / cos x = 1
cos x = 1
Where does cos x = 1??
Refer to the exact values chart to find that!
cos x = 1 when x = 0.
So, the correct answer is a